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Proof step 62 from proof validrefs-put-notin (previous step)

∀ str, ty, st, r, sk, val. (validrefs(str, acc, ty, st[r -- sk, val]) ↔ validrefs(str, acc, ty, st)) ∨ r ∈ acc ⊦ validrefs(str, r0 + acc, ty, st[r -- sk, val]) ↔ validrefs(str, r0 + acc, ty, st), r ∈ r0 + acc

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 61:
∀ str, ty, st, r, sk, val. (validrefs(str, acc, ty, st[r -- sk, val]) ↔ validrefs(str, acc, ty, st)) ∨ r ∈ acc ⊦ validrefs(str, r0 ' + acc, ty, st[r -- sk, val]) ↔ validrefs(str, r0 ' + acc, ty, st), r = r0, r ∈ acc

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ ¬ r ∈ r0 ' + refs ↔ r ≠ r0 ∧ ¬ r ∈ refs], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]