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Proof step 63 from proof validrefs-subset-01 (previous step)

is_array(str, r0, st0) ∧ st0[r0 -- _type] .type ≤ ty, is_array(str, r0, st), st ⊆ st0, st[r0 -- _type] .type ≤ ty, ∀ str0, ty0, st1, st2. validrefs(str0, acc, ty0, st1) ∧ st1 ⊆ st2 ∧ ¬ junkref(str0, acc .first, st1) ∧ acc ≠ [] → validrefs(str0, acc, ty0, st2), acc = [] ∨ 0 ≤ i ∧ i < st[r0 -- _length] .intval ∧ is_referencevalue(st[r0 -- i ']) ∧ acc .first = st[r0 -- i '] .refval ∧ validrefs(str, acc, st[r0 -- _type] .type .type, st) ⊦ r0 = jvmref, junkref(str, r0, st), acc = [] ∨ (∃ i. 0 ≤ i ∧ i < st0[r0 -- _length] .intval ∧ is_referencevalue(st0[r0 -- i ']) ∧ acc .first = st0[r0 -- i '] .refval ∧ validrefs(str, acc, st0[r0 -- _type] .type .type, st0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 62:
acc .first = st[r0 -- i '] .refval, st0[r0 -- _type] .type ≤ ty, is_array(str, r0, st), st ⊆ st0, st[r0 -- _type] .type ≤ ty, i < st[r0 -- _length] .intval, is_referencevalue(st[r0 -- i ']), validrefs(str, acc, st[r0 -- _type] .type .type, st), 0 ≤ i, 0 < st[r0 -- _length] .intval, ∀ str0, ty0, st1, st2. validrefs(str0, acc, ty0, st1) ∧ st1 ⊆ st2 ∧ ¬ junkref(str0, acc .first, st1) → validrefs(str0, acc, ty0, st2) ⊦ r0 = jvmref, acc = [], junkref(str, r0, st), ∃ i0. ¬ i0 < 0 ∧ ¬ st0[r0 -- _length] .intval ≤ i0 ∧ is_referencevalue(st0[r0 -- i0 ']) ∧ acc .first = st0[r0 -- i0 '] .refval ∧ validrefs(str, acc, st0[r0 -- _type] .type .type, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j], [CSIMPSEQ : ⊦ ¬ i < j ↔ j ≤ i], [CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i], [CSIMPSEQ : ⊦ st ⊆ st1 ∧ is_array(str, r, st) → is_array(str, r, st1)])]]