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Proof step 51 from proof validrefs-subset (previous step)

is_array(str, r0, st), st ⊆ st0, is_valid_ref(str, r0, st0), st0[r0 -- _type] .type ≤ ty, ∀ str0, ty0, st1, st2. validrefs(str0, acc, ty0, st1) ∧ st2 ⊆ st1 ∧ ¬ junkref(str0, acc .first, st2) ∧ acc ≠ [] → validrefs(str0, acc, ty0, st2), acc = [] ∨ 0 ≤ i ∧ i < st0[r0 -- _length] .intval ∧ is_referencevalue(st0[r0 -- i ']) ∧ acc .first = st0[r0 -- i '] .refval ∧ validrefs(str, acc, st0[r0 -- _type] .type .type, st0) ⊦ r0 = jvmref, validrefs(str, r0 ' + acc, ty, st), st[r0 -- _type] .type ≤ ty, ¬ i < 0 ∧ ¬ st[r0 -- _length] .intval ≤ i ∧ is_referencevalue(st[r0 -- i ']) ∧ st[r0 -- i '] .refval ≠ jvmref ∧ (¬ st[st[r0 -- i '] .refval -- _type] .type ≤ st[r0 -- _type] .type .type ∨ junkref(str, st[r0 -- i '] .refval, st))

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[speclemmaarg: ,st1 ⊆ st2 ↔ (∀ rk. rk ∈ st1 → rk ∈ st2 ∧ st1[rk] = st2[rk]) ,[st2, st1] → [st0, st] ,F ,store ,javastore-ostorea ,Subset ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st0, st)]]