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Proof step 86 from proof validrefs-subset (previous step)

is_array(str, r0, st0) ∧ st0[r0 -- _type] .type ≤ ty, is_array(str, r0, st), acc = [] ∨ (∃ i. 0 ≤ i ∧ i < st0[r0 -- _length] .intval ∧ is_referencevalue(st0[r0 -- i ']) ∧ acc .first = st0[r0 -- i '] .refval ∧ validrefs(str, acc, st0[r0 -- _type] .type .type, st0)), st ⊆ st0, is_valid_ref(str, r0, st0), st0[r0 -- _type] .type ≤ ty, ∀ str0, ty0, st1, st2. validrefs(str0, acc, ty0, st1) ∧ st2 ⊆ st1 ∧ ¬ junkref(str0, acc .first, st2) ∧ acc ≠ [] → validrefs(str0, acc, ty0, st2) ⊦ r0 = jvmref, junkref(str, r0, st), validrefs(str, r0 ' + acc, ty, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 85:
is_array(str, r0, st), st ⊆ st0, is_valid_ref(str, r0, st0), st0[r0 -- _type] .type ≤ ty, ∀ str0, ty0, st1, st2. validrefs(str0, acc, ty0, st1) ∧ st2 ⊆ st1 ∧ ¬ junkref(str0, acc .first, st2) ∧ acc ≠ [] → validrefs(str0, acc, ty0, st2), acc = [] ∨ 0 ≤ i ∧ i < st0[r0 -- _length] .intval ∧ is_referencevalue(st0[r0 -- i ']) ∧ acc .first = st0[r0 -- i '] .refval ∧ validrefs(str, acc, st0[r0 -- _type] .type .type, st0) ⊦ r0 = jvmref, junkref(str, r0, st), validrefs(str, r0 ' + acc, ty, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ st ⊆ st1 ∧ is_array(str, r, st) → is_array(str, r, st1)])]]