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Proof step 96 from proof validrefs-subset (previous step)

st ⊆ st0, validrefs(str, r0 ' + acc, ty, st0), ∀ str0, ty0, st1, st2. validrefs(str0, acc, ty0, st1) ∧ st2 ⊆ st1 ∧ ¬ junkref(str0, acc .first, st2) ∧ acc ≠ [] → validrefs(str0, acc, ty0, st2) ⊦ validrefs(str, r0 ' + acc, ty, st), junkref(str, r0, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ r = jvmref → (validrefs(str, r ' + refs, ty, st) ↔ refs = [])
Proof step 94:
r0 ≠ jvmref, st ⊆ st0, validrefs(str, r0 ' + acc, ty, st0), ∀ str0, ty0, st1, st2. validrefs(str0, acc, ty0, st1) ∧ st2 ⊆ st1 ∧ ¬ junkref(str0, acc .first, st2) ∧ acc ≠ [] → validrefs(str0, acc, ty0, st2) ⊦ validrefs(str, r0 ' + acc, ty, st), junkref(str, r0, st)
Proof step 95:
⊦ validrefs(str, jvmref ', ty, st)

Rule argument

[crewrite-arg: validrefs-null , F , [st, ty, refs, r, str] → [st0, ty, acc, r0, str] ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ refs + [] = refs], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1])], [EXTRATERMS : (st0, ty, acc, r0, str)]]