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Proof step 4 from proof validrefs-superset-junkref (previous step)

validrefs(str, r ' + refs, ty, st0) ∧ st ⊆ st0 ∧ ¬ junkref(str, r, st) ∧ r ' + refs ≠ [] ∧ (r ' + refs) .first = r → validrefs(str, r ' + refs, ty, st), validrefs(str, r ' + refs, ty, st0), r0 ∈ refs, newref(r0, st), st ⊆ st0 ⊦ r0 = jvmref, junkref(str, r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
validrefs(str, r ' + refs, ty, st0), r0 ∈ refs, newref(r0, st), st ⊆ st0, validrefs(str, r ' + refs, ty, st) ⊦ r0 = jvmref, junkref(str, r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (r ' + refs) .first = r], [CSIMPSEQ : ⊦ r ' ≠ []], [CSIMPSEQ : ⊦ ¬ refs + refs0 ≠ [] ↔ refs = [] ∧ refs0 = []], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1])]]