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Proof step 34 from proof validrefs-trans-01 (previous step)

acc .first = st[r -- i '] .refval, st[r -- _type] .type ≤ ty, validrefs(str, acc .last ' + refs1, ty0, st), is_array(str, r, st), i < st[r -- _length] .intval, is_referencevalue(st[r -- i ']), validrefs(str, acc, st[r -- _type] .type .type, st), 0 ≤ i, 0 < st[r -- _length] .intval, ∀ str0, ty1, st0, refs, ty2. validrefs(str0, acc, ty1, st0) ∧ validrefs(str0, acc .last ' + refs, ty2, st0) → validrefs(str0, acc + refs, ty1, st0) ⊦ acc = [], r = jvmref, validrefs(str, (r ' + acc) + refs1, ty, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 33:
acc = r0 + refs0, r0 = st[r -- i '] .refval, st[r -- _type] .type ≤ ty, validrefs(str, acc .last ' + refs1, ty0, st), is_array(str, r, st), i < st[r -- _length] .intval, is_referencevalue(st[r -- i ']), validrefs(str, acc, st[r -- _type] .type .type, st), 0 ≤ i, 0 < st[r -- _length] .intval, ∀ str0, ty1, st0, refs, ty2. validrefs(str0, acc, ty1, st0) ∧ validrefs(str0, acc .last ' + refs, ty2, st0) → validrefs(str0, acc + refs, ty1, st0) ⊦ acc = [], r = jvmref, validrefs(str, (r ' + acc) + refs1, ty, st)

Rule argument

[speclemmaarg: refs ≠ [] ,r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0 ,[refs, r, refs0] → [acc, r0, refs0] ,T ,list-data ,references-olista ,elim-list-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : refs ≠ [] ⊦ r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0])], [EXTRATERMS : (acc, r0, refs0)]]