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Proof step 65 from proof validrefs-trans-01 (previous step)

∀ str, ty, st, refs1, ty0. validrefs(str, acc, ty, st) ∧ validrefs(str, acc .last ' + refs1, ty0, st) → acc = [] ∨ validrefs(str, acc + refs1, ty, st), validrefs(str, r + acc, ty, st), validrefs(str, (r + acc) .last ' + refs1, ty0, st) ⊦ r + acc = [], validrefs(str, (r + acc) + refs1, ty, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 64:
validrefs(str, r ' + acc, ty, st), validrefs(str, (r ' + acc) .last ' + refs1, ty0, st), ∀ str, ty, st, refs1, ty0. validrefs(str, acc, ty, st) ∧ validrefs(str, acc .last ' + refs1, ty0, st) → acc = [] ∨ validrefs(str, acc + refs1, ty, st) ⊦ validrefs(str, (r ' + acc) + refs1, ty, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ r ' + refs ≠ []], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]