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Proof step 67 from proof validrefs-trans-01 (conclusion)

⊦ refs ≠ [] ∧ validrefs(str, refs, ty, st) ∧ validrefs(str, refs .last + refs1, ty0, st) → validrefs(str, refs + refs1, ty, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 66:
validrefs(str, refs, ty, st), validrefs(str, refs .last ' + refs1, ty0, st) ⊦ refs = [], validrefs(str, refs + refs1, ty, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r + refs = r ' + refs])]]