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Proof step 28 from proof all-classes-02 (previous step)

∀ rks0. # rks0 < # rks → (true → (∃ str. ∀ rk. rk ∈ rks0 ∧ is_fskey(rk .key) → ¬ # str ≤ # rk .key .fs .class .class)) ⊦ # rks = 0, rks = ∅, ∃ str. ∀ rk. rk ∈ rks ∧ is_fskey(rk .key) → ¬ # str ≤ # rk .key .fs .class .class

User applied rule insert spec-lemma

And obtained the following new goals

Proof step 1:
⊦ rks = ∅ ∨ (∃ rk. rk ∈ rks)
Proof step 27:
∃ rk. rk ∈ rks, ∀ rks0. # rks0 < # rks → (true → (∃ str. ∀ rk. rk ∈ rks0 ∧ is_fskey(rk .key) → ¬ # str ≤ # rk .key .fs .class .class)) ⊦ # rks = 0, rks = ∅, ∃ str. ∀ rk. rk ∈ rks ∧ is_fskey(rk .key) → ¬ # str ≤ # rk .key .fs .class .class

Rule argument

[speclemmaarg: ,rks = ∅ ∨ (∃ rk. rk ∈ rks) ,[rks] → [rks] ,F ,set-basic ,javastore ,sel ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (rks)]]