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Proof step 2 from proof look-del (conclusion)

⊦ r ≠ r0 → (st -- (r -- sk))[r0 -- sk] = st[r0 -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ r ≠ r0 → (st -- (r -- sk))[r0 -- sk0] = st[r0 -- sk0]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]