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Proof step 1 from proof refp (conclusion)

⊦ rk ≠ rk0 → (refp((st -- rk)[rk0]) ↔ refp(st[rk0]))

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ rk ≠ rk0 → (st -- rk0)[rk] = st[rk]])]]