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Proof step 5 from proof initsubset-initdone-forward (conclusion)

⊦ init⊆(str, st, st0) ∧ initdone(class, st) → initdone(class, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
initdone(class, st), init⊆(str, st, st0) ⊦ initdone(class, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]