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Proof step 5 from proof initsubset-mode (previous step)

¬ (init⊆(str, st, st0[_mode, val]) ∧ init⊆(str, st0[_mode, val], st0)), init⊆(str, st, st0[_mode, val]) ⊦ init⊆(str, st, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ init⊆(str, st[_mode, val], st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]