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Proof step 7 from proof initsubset-mode (previous step)

¬ (init⊆(str, st, st0) ∧ init⊆(str, st0, st0[_mode, val])) ⊦ init⊆(str, st, st0[_mode, val]) ↔ init⊆(str, st, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ init⊆(str, st, st[_mode, val])
Proof step 6:
init⊆(str, st, st0[_mode, val]) ⊦ init⊆(str, st, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]