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Proof step 43 from proof initsubset-trans (conclusion)

⊦ init⊆(str, st, st0) ∧ init⊆(str, st0, st1) → init⊆(str, st, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 42:
init⊆(str, st0, st1), init⊆(str, st, st0) ⊦ init⊆(str, st, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]