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Proof step 19 from proof junkref-array (previous step)

∃ refs. refs ≠ [] ∧ refs .first = r ∧ junkrefs(str, refs, st[refs .first -- _type] .type, st), is_array(str, r, st) ⊦ ∃ i. ¬ i < 0 ∧ ¬ st[r -- _length] .intval ≤ i ∧ is_referencevalue(st[r -- i ']) ∧ st[r -- i '] .refval ≠ jvmref ∧ (¬ st[st[r -- i '] .refval -- _type] .type ≤ st[r -- _type] .type .type ∨ junkref(str, st[r -- i '] .refval, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
junkrefs(str, refs, st[refs .first -- _type] .type, st), is_array(str, refs .first, st) ⊦ refs = [], ∃ i. ¬ i < 0 ∧ ¬ st[refs .first -- _length] .intval ≤ i ∧ is_referencevalue(st[refs .first -- i ']) ∧ st[refs .first -- i '] .refval ≠ jvmref ∧ (¬ st[st[refs .first -- i '] .refval -- _type] .type ≤ st[refs .first -- _type] .type .type ∨ junkref(str, st[refs .first -- i '] .refval, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]