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Proof step 45 from proof junkref-array (previous step)

is_referencevalue(st[r -- i ']), is_array(str, r, st), i < st[r -- _length] .intval, 0 ≤ i, 0 < st[r -- _length] .intval, ¬ st[st[r -- i '] .refval -- _type] .type ≤ st[r -- _type] .type .type ∨ junkref(str, st[r -- i '] .refval, st) ⊦ st[r -- i '] .refval = jvmref, ∃ refs. refs ≠ [] ∧ refs .first = r ∧ junkrefs(str, refs, st[refs .first -- _type] .type, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 44:
st[r -- i '] = refval(r0), is_referencevalue(st[r -- i ']), is_array(str, r, st), i < st[r -- _length] .intval, 0 ≤ i, 0 < st[r -- _length] .intval, ¬ st[r0 -- _type] .type ≤ st[r -- _type] .type .type ∨ junkref(str, r0, st) ⊦ r0 = jvmref, ∃ refs. refs ≠ [] ∧ refs .first = r ∧ junkrefs(str, refs, st[refs .first -- _type] .type, st)

Rule argument

[speclemmaarg: ,is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) ,[val, r] → [st[r -- i '], r0] ,T ,javavalue , ,elim-13 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (st[r -- i '], r0)]]