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Proof step 3 from proof junkref-levelsubset-01 (conclusion)
⊦ level⊆(str, str0) ∧ ¬ junkref(str, r, st) → (junkref(str0, r, st) ↔ false)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
level⊆(str, str0), junkref(str0, r, st) ⊦ junkref(str, r, st)
Rule argument
[emptyarg]
Additional information
[[CONCRETESIMPRULES : ()]]