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Proof step 31 from proof junkref-put-badfield (previous step)

∃ refs. refs ≠ [] ∧ refs .first = r ∧ junkrefs(str, refs, (st[r0 -- fs ', val][r -- _type]) .type, st[r0 -- fs ', val]) ⊦ junkref(str, r, st), is_typevalue(st[r0 -- _type]) ∧ is_reftype(st[r0 -- _type] .type)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
junkrefs(str, refs, (st[r0 -- fs ', val][refs .first -- _type]) .type, st[r0 -- fs ', val]) ⊦ refs = [], junkref(str, refs .first, st), is_typevalue(st[r0 -- _type]) ∧ is_reftype(st[r0 -- _type] .type)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]