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Proof step 12 from proof junkref-put-field (previous step)

mkfs(class, ty, fieldvar) ' ∈ instfields(st[refs .first -- _type] .type .class), st[r0 -- _type] .type ≤ ty, is_obj(refs .first, st), junkrefs (str, refs, (st[refs .first -- mkfs(class, ty, fieldvar) ', refval(r0)][refs .first -- _type]) .type, st[refs .first -- mkfs(class, ty, fieldvar) ', refval(r0)]) ⊦ r0 = jvmref, refs = [], junkref(str, r0, st), junkref(str, refs .first, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 11:
refs = r + refs0, mkfs(class, ty, fieldvar) ' ∈ instfields(st[r -- _type] .type .class), st[r0 -- _type] .type ≤ ty, is_obj(r, st), junkrefs(str, refs, (st[r -- mkfs(class, ty, fieldvar) ', refval(r0)][r -- _type]) .type, st[r -- mkfs(class, ty, fieldvar) ', refval(r0)]) ⊦ r0 = jvmref, refs = [], junkref(str, r0, st), junkref(str, r, st)

Rule argument

[speclemmaarg: refs ≠ [] ,r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0 ,[refs, r, refs0] → [refs, r, refs0] ,T ,list-data ,references ,elim-list-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : refs ≠ [] ⊦ r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0])], [EXTRATERMS : (refs, r, refs0)]]