[Imprint]
[Data Privacy Statement]
[E-Mail]
View
long theorem info
. View
the proof
. Back to
main index
. View
the specification
. View
theorem base summary
, View
theorem base listing
, the
used properties by spec
, the
dependency list
, the
symbol table
,
Proof step 12 from proof junkref-union-disjoint (
previous step
)
⊦ st1 .refs ∩ st .refs = ∅ ∧ r ∈ st1 ∧ junkrefs(str, r ' + refs0, ty, st1 ∪ st) → junkrefs(str, r ' + refs0, ty, st1)
Lemma
junkrefs-union-disjoint