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Proof step 4 from proof junkreflist-rec (previous step)

junkref(str, r, st), refval(r) = val ∨ refval(r) ∈ vals ⊦ ∃ r. refval(r) ∈ vals ∧ junkref(str, r, st), is_referencevalue(val) ∧ junkref(str, val .refval, st)

User applied rule case distinction

And obtained the following new goals

Proof step 3:
refval(r) ∈ vals, junkref(str, r, st) ⊦ ∃ r. refval(r) ∈ vals ∧ junkref(str, r, st), is_referencevalue(val) ∧ junkref(str, val .refval, st)

Rule argument

[CASEDARG : pos: left 2, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ is_referencevalue(refval(r))], [CSIMPSEQ : ⊦ refval(r) .refval = r])]]