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Proof step 8 from proof junkreflist-rec (previous step)

junkref(str, val .refval, st), is_referencevalue(val) ⊦ ∃ r. (refval(r) = val ∨ refval(r) ∈ vals) ∧ junkref(str, r, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 7:
val = refval(r0), junkref(str, r0, st), is_referencevalue(val) ⊦ ∃ r. (refval(r) = val ∨ refval(r) ∈ vals) ∧ junkref(str, r, st)

Rule argument

[speclemmaarg: ,is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) ,[val, r] → [val, r0] ,T ,javavalue , ,elim-13 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (val, r0)]]