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Proof step 17 from proof junkrefs-append (previous step)

acc .first = st[r -- fs '] .refval, st[r -- _type] .type ≤ ty, junkrefs(str, acc, fs .type, st), is_referencevalue(st[r -- fs ']), fs ' ∈ instfields(st[r -- _type] .type .class), is_obj(str, r, st), ∀ str, ty, st, refs0. junkrefs(str, acc, ty, st) → junkrefs(str, acc + refs0, ty, st) ⊦ acc = [], r = jvmref, junkrefs(str, (r ' + acc) + refs0, ty, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 16:
acc = r0 + refs, r0 = st[r -- fs '] .refval, st[r -- _type] .type ≤ ty, junkrefs(str, acc, fs .type, st), is_referencevalue(st[r -- fs ']), fs ' ∈ instfields(st[r -- _type] .type .class), is_obj(str, r, st), ∀ str, ty, st, refs0. junkrefs(str, acc, ty, st) → junkrefs(str, acc + refs0, ty, st) ⊦ acc = [], r = jvmref, junkrefs(str, (r ' + acc) + refs0, ty, st)

Rule argument

[speclemmaarg: refs ≠ [] ,r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0 ,[refs, r, refs0] → [acc, r0, refs] ,T ,list-data ,references-olista ,elim-list-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : refs ≠ [] ⊦ r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0])], [EXTRATERMS : (acc, r0, refs)]]