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Proof step 2 from proof junkrefs-delete-01 (previous step)

junkrefs(str, refs, ty, st -- r) ⊦ junkrefs(str, refs, ty, st), r ∈ refs

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ junkrefs(str, refs, ty, st -- r) ∧ ¬ r ∈ refs → junkrefs(str, refs, ty, st)

Rule argument

[crewrite-arg: junkrefs-delete , F , [str, refs, ty, st, r] → [str, refs, ty, st, r] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (str, refs, ty, st, r)]]