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Proof step 32 from proof junkrefs-levelsubset (previous step)

level⊆(str, str0), st[r -- _type] .type ≤ ty, 0 ≤ i, 0 < st[r -- _length] .intval, is_array(str0, r, st), is_array(str, r, st), i < st[r -- _length] .intval, is_referencevalue(st[r -- i ']), junkrefs(str0, st[r -- i '] .refval ' + refs, st[r -- _type] .type .type, st), ∀ str1, str2, ty0, st0. level⊆(str1, str2) ∧ junkrefs(str2, st[r -- i '] .refval ' + refs, ty0, st0) → junkrefs(str1, st[r -- i '] .refval ' + refs, ty0, st0) ⊦ r = jvmref, junkrefs(str, r ' + st[r -- i '] .refval ' + refs, ty, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 31:
st[r -- i '] = refval(r0), level⊆(str, str0), st[r -- _type] .type ≤ ty, 0 ≤ i, 0 < st[r -- _length] .intval, is_array(str0, r, st), is_array(str, r, st), i < st[r -- _length] .intval, is_referencevalue(st[r -- i ']), junkrefs(str0, r0 ' + refs, st[r -- _type] .type .type, st), ∀ str1, str2, ty0, st0. level⊆(str1, str2) ∧ junkrefs(str2, r0 ' + refs, ty0, st0) → junkrefs(str1, r0 ' + refs, ty0, st0) ⊦ r = jvmref, junkrefs(str, r ' + r0 ' + refs, ty, st)

Rule argument

[speclemmaarg: ,is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) ,[val, r] → [st[r -- i '], r0] ,T ,javavalue , ,elim-13 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (st[r -- i '], r0)]]