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Proof step 34 from proof junkrefs-levelsubset (previous step)

acc .first = st[r -- i '] .refval, is_array(str0, r, st), is_array(str, r, st), i < st[r -- _length] .intval, is_referencevalue(st[r -- i ']), junkrefs(str0, acc, st[r -- _type] .type .type, st), level⊆(str, str0), st[r -- _type] .type ≤ ty, 0 ≤ i, 0 < st[r -- _length] .intval, ∀ str, str0, ty, st. level⊆(str, str0) ∧ junkrefs(str0, acc, ty, st) → junkrefs(str, acc, ty, st) ⊦ r = jvmref, acc = [], junkrefs(str, r ' + acc, ty, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 33:
acc = r0 + refs, r0 = st[r -- i '] .refval, is_array(str0, r, st), is_array(str, r, st), i < st[r -- _length] .intval, is_referencevalue(st[r -- i ']), junkrefs(str0, acc, st[r -- _type] .type .type, st), level⊆(str, str0), st[r -- _type] .type ≤ ty, 0 ≤ i, 0 < st[r -- _length] .intval, ∀ str, str0, ty, st. level⊆(str, str0) ∧ junkrefs(str0, acc, ty, st) → junkrefs(str, acc, ty, st) ⊦ r = jvmref, acc = [], junkrefs(str, r ' + acc, ty, st)

Rule argument

[speclemmaarg: refs ≠ [] ,r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0 ,[refs, r, refs0] → [acc, r0, refs] ,T ,list-data ,references-olista ,elim-list-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : refs ≠ [] ⊦ r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0])], [EXTRATERMS : (acc, r0, refs)]]