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Proof step 61 from proof junkrefs-notin (conclusion)

⊦ ¬ r ∈ st → (junkrefs(str, refs + r ' + refs0, ty, st) ↔ junkrefs(str, refs + r ', ty, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 60:
⊦ junkrefs(str, refs + r ' + refs0, ty, st) ↔ junkrefs(str, refs + r ', ty, st), r ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]