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Proof step 33 from proof junkrefs-put-array-norefval (previous step)

0 ≤ i0, 0 < st[r -- _length] .intval, is_array(str, r, st[r1 -- i ', val]), st[r -- _type] .type ≤ ty, is_array(str, r, st), okval(val, st[r1 -- _type] .type .type), i0 < st[r -- _length] .intval, is_referencevalue(st[r1 -- i ', val][r -- i0 ']), junkrefs(str, (st[r1 -- i ', val][r -- i0 ']) .refval ' + refs, st[r -- _type] .type .type, st[r1 -- i ', val]), ∀ val0, st0, r0, str0, ty0, i1. okval(val0, st0[r0 -- _type] .type .type) ∧ junkrefs(str0, (st[r1 -- i ', val][r -- i0 ']) .refval ' + refs, ty0, st0[r0 -- i1 ', val0]) → is_referencevalue(val0) ∨ junkrefs(str0, (st[r1 -- i ', val][r -- i0 ']) .refval ' + refs, ty0, st0) ⊦ r = jvmref, is_referencevalue(val), junkrefs(str, r ' + (st[r1 -- i ', val][r -- i0 ']) .refval ' + refs, ty, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 32:
(st[r1 -- i ', val][r -- i0 ']) = refval(r2), 0 ≤ i0, 0 < st[r -- _length] .intval, is_array(str, r, st[r1 -- i ', val]), st[r -- _type] .type ≤ ty, is_array(str, r, st), okval(val, st[r1 -- _type] .type .type), i0 < st[r -- _length] .intval, is_referencevalue(st[r1 -- i ', val][r -- i0 ']), junkrefs(str, r2 ' + refs, st[r -- _type] .type .type, st[r1 -- i ', val]), ∀ val0, st0, r0, str0, ty0, i1. okval(val0, st0[r0 -- _type] .type .type) ∧ junkrefs(str0, r2 ' + refs, ty0, st0[r0 -- i1 ', val0]) → is_referencevalue(val0) ∨ junkrefs(str0, r2 ' + refs, ty0, st0) ⊦ r = jvmref, is_referencevalue(val), junkrefs(str, r ' + r2 ' + refs, ty, st)

Rule argument

[speclemmaarg: ,is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) ,[val, r] → [st[r1 -- i ', val][r -- i0 '], r2] ,T ,javavalue , ,elim-13 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (st[r1 -- i ', val][r -- i0 '], r2)]]