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Proof step 63 from proof junkrefs-put-badfield (previous step)

acc .first = st[r -- i '] .refval, junkrefs(str, acc, (st[r0 -- fs ', val][r -- _type]) .type .type, st[r0 -- fs ', val]), st[r -- _type] .type ≤ ty, is_array(str, r, st[r0 -- fs ', val]), (st[r0 -- fs ', val][r -- _type]) .type ≤ ty, is_array(str, r, st), i < (st[r0 -- fs ', val][r -- _length]) .intval, is_referencevalue(st[r -- i ']), 0 ≤ i, 0 < (st[r0 -- fs ', val][r -- _length]) .intval, ∀ str, ty, st, r0, fs, val. junkrefs(str, acc, ty, st[r0 -- fs ', val]) → junkrefs(str, acc, ty, st) ∨ is_typevalue(st[r0 -- _type]) ∧ is_reftype(st[r0 -- _type] .type) ⊦ r = jvmref, acc = [], junkrefs(str, r ' + acc, ty, st), is_typevalue(st[r0 -- _type]) ∧ is_reftype(st[r0 -- _type] .type)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

[speclemmaarg: refs ≠ [] ,r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0 ,[refs, r, refs0] → [acc, r1, refs] ,T ,list-data ,references-olista ,elim-list-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : refs ≠ [] ⊦ r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0])], [EXTRATERMS : (acc, r1, refs)]]