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Proof step 61 from proof junkrefs-put-notin (conclusion)

⊦ ¬ r ∈ refs → (junkrefs(str, refs, ty, st[r -- sk, val]) ↔ junkrefs(str, refs, ty, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 60:
⊦ junkrefs(str, refs, ty, st[r -- sk, val]) ↔ junkrefs(str, refs, ty, st), r ∈ refs

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]