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Proof step 62 from proof junkrefs-subset (previous step)

st ⊆ st1, junkrefs(str, r ' + acc, ty, st1), ∀ str, ty, st1, st. junkrefs(str, acc, ty, st1) ∧ st ⊆ st1 → junkrefs(str, acc, ty, st) ⊦ junkrefs(str, r ' + acc, ty, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ r = jvmref → ¬ junkrefs(str, r ' + refs, ty, st)
Proof step 61:
r ≠ jvmref, st ⊆ st1, junkrefs(str, r ' + acc, ty, st1), ∀ str, ty, st1, st. junkrefs(str, acc, ty, st1) ∧ st ⊆ st1 → junkrefs(str, acc, ty, st) ⊦ junkrefs(str, r ' + acc, ty, st)

Rule argument

[crewrite-arg: junkrefs-null , F , [st, ty, refs, r, str] → [st1, ty, acc, r, str] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st1, ty, acc, r, str)]]