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Proof step 111 from proof junkrefs-union-disjoint (previous step)

is_array(str, r, st1) ∧ st1[r -- _type] .type ≤ ty, is_array(str, r, st1), st1 .refs ∩ st .refs = ∅, junkrefs(str, r ' + r0 ' + acc, ty, st1 ∪ st), r ∈ st1, st1[r -- _type] .type ≤ ty, ∀ st1, st, r, str, ty. st1 .refs ∩ st .refs = ∅ ∧ r ∈ st1 ∧ junkrefs(str, r ' + acc, ty, st1 ∪ st) → junkrefs(str, r ' + acc, ty, st1) ⊦ r = jvmref, r0 ' + acc ≠ [] ∧ (∃ i. 0 ≤ i ∧ i < st1[r -- _length] .intval ∧ is_referencevalue(st1[r -- i ']) ∧ (r0 ' + acc) .first = st1[r -- i '] .refval ∧ junkrefs(str, r0 ' + acc, st1[r -- _type] .type .type, st1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 110:
st1 .refs ∩ st .refs = ∅, is_array(str, r, st1), junkrefs(str, r ' + r0 ' + acc, ty, st1 ∪ st), r ∈ st1, st1[r -- _type] .type ≤ ty, ∀ st1, st, r, str, ty. st1 .refs ∩ st .refs = ∅ ∧ r ∈ st1 ∧ junkrefs(str, r ' + acc, ty, st1 ∪ st) → junkrefs(str, r ' + acc, ty, st1) ⊦ r = jvmref, ∃ i. ¬ i < 0 ∧ ¬ st1[r -- _length] .intval ≤ i ∧ is_referencevalue(st1[r -- i ']) ∧ r0 = st1[r -- i '] .refval ∧ junkrefs(str, st1[r -- i '] .refval ' + acc, st1[r -- _type] .type .type, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (r ' + refs) .first = r], [CSIMPSEQ : ⊦ ¬ i < j ↔ j ≤ i], [CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i], [CSIMPSEQ : ⊦ r ' ≠ []], [CSIMPSEQ : ⊦ ¬ refs + refs0 ≠ [] ↔ refs = [] ∧ refs0 = []], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1])]]