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Proof step 115 from proof junkrefs-union-disjoint (previous step)

¬ (r ≠ jvmref ∧ (¬ is_valid_ref(str, r, st1) ∨ ¬ st1[r -- _type] .type ≤ ty)), st1 .refs ∩ st .refs = ∅, junkrefs(str, r ' + r0 ' + acc, ty, st1 ∪ st), r ∈ st1, ∀ st1, st, r, str, ty. st1 .refs ∩ st .refs = ∅ ∧ r ∈ st1 ∧ junkrefs(str, r ' + acc, ty, st1 ∪ st) → junkrefs(str, r ' + acc, ty, st1) ⊦ r = jvmref, junkrefs(str, r ' + r0 ' + acc, ty, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 114:
st1 .refs ∩ st .refs = ∅, junkrefs(str, r ' + r0 ' + acc, ty, st1 ∪ st), r ∈ st1, is_valid_ref(str, r, st1), st1[r -- _type] .type ≤ ty, ∀ st1, st, r, str, ty. st1 .refs ∩ st .refs = ∅ ∧ r ∈ st1 ∧ junkrefs(str, r ' + acc, ty, st1 ∪ st) → junkrefs(str, r ' + acc, ty, st1) ⊦ r = jvmref, junkrefs(str, r ' + r0 ' + acc, ty, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1])]]