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Proof step 117 from proof junkrefs-union-disjoint (previous step)

r ≠ jvmref, st1 .refs ∩ st .refs = ∅, r ∈ st1, junkrefs(str, r ' + r0 ' + acc, ty, st1 ∪ st), ∀ st1, st, r, str, ty. st1 .refs ∩ st .refs = ∅ ∧ r ∈ st1 ∧ junkrefs(str, r ' + acc, ty, st1 ∪ st) → junkrefs(str, r ' + acc, ty, st1) ⊦ junkrefs(str, r ' + r0 ' + acc, ty, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 116:
st1 .refs ∩ st .refs = ∅, junkrefs(str, r ' + r0 ' + acc, ty, st1 ∪ st), r ∈ st1, ∀ st1, st, r, str, ty. st1 .refs ∩ st .refs = ∅ ∧ r ∈ st1 ∧ junkrefs(str, r ' + acc, ty, st1 ∪ st) → junkrefs(str, r ' + acc, ty, st1) ⊦ r = jvmref, junkrefs(str, r ' + r0 ' + acc, ty, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1])]]