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Proof step 98 from proof junkrefs-union-disjoint (previous step)

st1 .refs ∩ st .refs = ∅, st1[r -- i '] = refval(r0), 0 < st1[r -- _length] .intval, st1[r -- _type] .type ≤ ty, is_array(str, r, st1), i < st1[r -- _length] .intval, junkrefs(str, r0 ' + acc, st1[r -- _type] .type .type, st1 ∪ st), r ∈ st1, 0 ≤ i, ∀ st1, st, r, str, ty. st1 .refs ∩ st .refs = ∅ ∧ r ∈ st1 ∧ junkrefs(str, r ' + acc, ty, st1 ∪ st) → junkrefs(str, r ' + acc, ty, st1) ⊦ r = jvmref, r -- _type ∈ st, junkrefs(str, r0 ' + acc, st1[r -- _type] .type .type, st1), r -- _length ∈ st, r -- i ' ∈ st

User applied rule all left

And obtained the following new goals

Rule argument

[EXRARG : pos: left 10, [extquanttermlist: (st1, st, r0, str, st1[r -- _type] .type .type) abort:F , discard:F , computed:T ]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1])], [EXTRATERMS : (st1, st, r0, str, st1[r -- _type] .type .type)]]