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Proof step 60 from proof junkrefs-union (previous step)

acc = r0 + refs, r0 = (st0 ∪ st)[r -- i '] .refval, (st0 ∪ st)[r -- _type] .type ≤ ty, is_array(str, r, st), i < (st0 ∪ st)[r -- _length] .intval, is_referencevalue((st0 ∪ st)[r -- i ']), junkrefs(str, acc, (st0 ∪ st)[r -- _type] .type .type, st0 ∪ st), st[r -- _type] .type ≤ ty, 0 ≤ i, 0 < (st0 ∪ st)[r -- _length] .intval, ∀ str, ty, st0, st. junkrefs(str, acc, ty, st0 ∪ st) → junkrefs(str, acc, ty, st) ⊦ r = jvmref, acc = [], ∃ i. ¬ i < 0 ∧ ¬ st[r -- _length] .intval ≤ i ∧ is_referencevalue(st[r -- i ']) ∧ r0 = st[r -- i '] .refval ∧ junkrefs(str, acc, st[r -- _type] .type .type, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 59:
st[r -- _type] .type ≤ ty, 0 ≤ i, 0 < (st0 ∪ st)[r -- _length] .intval, (st0 ∪ st)[r -- _type] .type ≤ ty, is_array(str, r, st), i < (st0 ∪ st)[r -- _length] .intval, is_referencevalue((st0 ∪ st)[r -- i ']), junkrefs(str, (st0 ∪ st)[r -- i '] .refval ' + refs, (st0 ∪ st)[r -- _type] .type .type, st0 ∪ st), ∀ str0, ty0, st1, st2. junkrefs(str0, (st0 ∪ st)[r -- i '] .refval ' + refs, ty0, st1 ∪ st2) → junkrefs(str0, (st0 ∪ st)[r -- i '] .refval ' + refs, ty0, st2) ⊦ r = jvmref, ∃ i0. ¬ i0 < 0 ∧ ¬ st[r -- _length] .intval ≤ i0 ∧ is_referencevalue(st[r -- i0 ']) ∧ (st0 ∪ st)[r -- i '] .refval = st[r -- i0 '] .refval ∧ junkrefs(str, (st0 ∪ st)[r -- i '] .refval ' + refs, st[r -- _type] .type .type, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ r ' + refs ≠ []], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]