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Proof step 62 from proof junkrefs-union (previous step)

is_array(str, r, st0 ∪ st) ∧ (st0 ∪ st)[r -- _type] .type ≤ ty, is_array(str, r, st), acc ≠ [] ∧ (∃ i. 0 ≤ i ∧ i < (st0 ∪ st)[r -- _length] .intval ∧ is_referencevalue((st0 ∪ st)[r -- i ']) ∧ acc .first = (st0 ∪ st)[r -- i '] .refval ∧ junkrefs(str, acc, (st0 ∪ st)[r -- _type] .type .type, st0 ∪ st)), st[r -- _type] .type ≤ ty, ∀ str, ty, st0, st. junkrefs(str, acc, ty, st0 ∪ st) → junkrefs(str, acc, ty, st) ⊦ r = jvmref, acc ≠ [] ∧ (∃ i. ¬ i < 0 ∧ ¬ st[r -- _length] .intval ≤ i ∧ is_referencevalue(st[r -- i ']) ∧ acc .first = st[r -- i '] .refval ∧ junkrefs(str, acc, st[r -- _type] .type .type, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 61:
acc .first = (st0 ∪ st)[r -- i '] .refval, (st0 ∪ st)[r -- _type] .type ≤ ty, is_array(str, r, st), i < (st0 ∪ st)[r -- _length] .intval, is_referencevalue((st0 ∪ st)[r -- i ']), junkrefs(str, acc, (st0 ∪ st)[r -- _type] .type .type, st0 ∪ st), st[r -- _type] .type ≤ ty, 0 ≤ i, 0 < (st0 ∪ st)[r -- _length] .intval, ∀ str, ty, st0, st. junkrefs(str, acc, ty, st0 ∪ st) → junkrefs(str, acc, ty, st) ⊦ r = jvmref, acc = [], ∃ i. ¬ i < 0 ∧ ¬ st[r -- _length] .intval ≤ i ∧ is_referencevalue(st[r -- i ']) ∧ acc .first = st[r -- i '] .refval ∧ junkrefs(str, acc, st[r -- _type] .type .type, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j], [CSIMPSEQ : ⊦ is_array(str, r, st) → is_array(str, r, st0 ∪ st)])]]