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Proof step 15 from proof levelsubset-trans (previous step)

level⊆(str0, str1), (∀ class. class∃(str, class) → class∃(str0, class)) ∧ (∀ class. interface∃(str, class) → interface∃(str0, class)) ⊦ (class∃(str, class) → class∃(str1, class)) ∧ (interface∃(str, class0) → interface∃(str1, class0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
level⊆(str0, str1), ∀ class. interface∃(str, class) → interface∃(str0, class), ∀ class. class∃(str, class) → class∃(str0, class) ⊦ (class∃(str, class) → class∃(str1, class)) ∧ (interface∃(str, class0) → interface∃(str1, class0))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]