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Proof step 19 from proof levelsubset-trans (conclusion)

⊦ level⊆(str, str0) ∧ level⊆(str0, str1) → level⊆(str, str1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
level⊆(str0, str1), level⊆(str, str0) ⊦ level⊆(str, str1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]