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Proof step 5 from proof same-subclasses-classex (conclusion)

⊦ ¬ class+∃(str, class) ∧ same-subclasses(class, str, str0) → ¬ class+∃(str0, class)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
same-subclasses(class, str, str0), class+∃(str0, class) ⊦ class+∃(str, class)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]