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Proof step 3 from proof same-subclasses-interfaceex-01 (previous step)

class ≤ class0, interface∃(str0, class), (∀ class1. class∃(str0, class1) ∧ class1 ≤ class0 → class∃(str, class1)) ∧ (∀ class1. interface∃(str0, class1) ∧ class1 ≤ class0 → interface∃(str, class1)) ⊦ interface∃(str, class)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
interface∃(str0, class), class ≤ class0, ∀ class1. interface∃(str0, class1) ∧ class1 ≤ class0 → interface∃(str, class1), ∀ class1. class∃(str0, class1) ∧ class1 ≤ class0 → class∃(str, class1) ⊦ interface∃(str, class)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]