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Proof step 3 from proof same-subclasses-interfaceex (previous step)

interface∃(str0, class), (∀ class0. class∃(str0, class0) ∧ class0 ≤ class → class∃(str, class0)) ∧ (∀ class0. interface∃(str0, class0) ∧ class0 ≤ class → interface∃(str, class0)) ⊦ interface∃(str, class)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
interface∃(str0, class), ∀ class0. interface∃(str0, class0) ∧ class0 ≤ class → interface∃(str, class0), ∀ class0. class∃(str0, class0) ∧ class0 ≤ class → class∃(str, class0) ⊦ interface∃(str, class)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]