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Proof step 5 from proof same-subclasses-interfaceex (conclusion)

⊦ interface∃(str0, class) ∧ ¬ interface∃(str, class) → ¬ same-subclasses(class, str, str0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
interface∃(str0, class), same-subclasses(class, str, str0) ⊦ interface∃(str, class)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]