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Proof step 24 from proof same-subclasses-is-array (previous step)

type∃(str0, st[r -- _type] .type) ∧ st[r -- _type] .type .jtelemtype ≠ void_type ∧ st[r -- _type] .type .jtelemtype ≠ abstract_type ∧ is_array(r, st), same-subclasses(st[r -- _type] .type .jtelemtype .class, str, str0), is_array(r, st) ⊦ st[r -- _type] .type .jtelemtype ≠ abstract_type ∧ st[r -- _type] .type .jtelemtype ≠ void_type ∧ type∃(str, st[r -- _type] .type)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
type∃(str0, st[r -- _type] .type), same-subclasses(st[r -- _type] .type .jtelemtype .class, str, str0), is_array(r, st) ⊦ st[r -- _type] .type .jtelemtype = abstract_type, st[r -- _type] .type .jtelemtype = void_type, type∃(str, st[r -- _type] .type)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]