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Proof step 10 from proof same-subclasses-subclass (previous step)

class0 ≤ class, same-subclasses(class, str, str0) ⊦ (∀ class1. class∃(str0, class1) ∧ class1 ≤ class0 → class∃(str, class1)) ∧ (∀ class1. interface∃(str0, class1) ∧ class1 ≤ class0 → interface∃(str, class1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
class0 ≤ class, same-subclasses(class, str, str0) ⊦ (class∃(str0, class1) ∧ class1 ≤ class0 → class∃(str, class1)) ∧ (interface∃(str0, class2) ∧ class2 ≤ class0 → interface∃(str, class2))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]