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Proof step 7 from proof same-subclasses-tdnameex-04 (previous step)

same-subclasses(class, str, str0), class∃(str0, class) ∨ interface∃(str0, class) ⊦ interface∃(str, class), class∃(str, class)

User applied rule case distinction

And obtained the following new goals

Proof step 4:
class∃(str0, class), same-subclasses(class, str, str0) ⊦ interface∃(str, class), class∃(str, class)
Proof step 6:
interface∃(str0, class), same-subclasses(class, str, str0) ⊦ interface∃(str, class), class∃(str, class)

Rule argument

[CASEDARG : pos: left 2, ()]

Additional information

[[CONCRETESIMPRULES : ()]]