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Proof step 2 from proof same-subclasses-tdnameex-05 (conclusion)

⊦ tdname∃(str0, class) ∧ ¬ tdname∃(str, class) ∧ class ≤ class0 → ¬ same-subclasses(class0, str, str0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ ¬ tdname∃(str, class0) ∧ tdname∃(str0, class0) ∧ class0 ≤ class → ¬ same-subclasses(class, str, str0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]