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Proof step 10 from proof same-subclasses-trans (previous step)

class1 ≤ class, interface∃(str1, class1), ∀ class0. class∃(str1, class0) ∧ class0 ≤ class → class∃(str0, class0), ∀ class0. interface∃(str1, class0) ∧ class0 ≤ class → interface∃(str0, class0), ∀ class0. interface∃(str0, class0) ∧ class0 ≤ class → interface∃(str, class0), ∀ class0. class∃(str0, class0) ∧ class0 ≤ class → class∃(str, class0) ⊦ interface∃(str, class1)

User applied rule all left

And obtained the following new goals

Proof step 9:
class1 ≤ class, interface∃(str1, class1), ∀ class0. class∃(str1, class0) ∧ class0 ≤ class → class∃(str0, class0), interface∃(str1, class1) ∧ class1 ≤ class → interface∃(str0, class1), ∀ class0. interface∃(str0, class0) ∧ class0 ≤ class → interface∃(str, class0), ∀ class0. class∃(str0, class0) ∧ class0 ≤ class → class∃(str, class0) ⊦ interface∃(str, class1)

Rule argument

[EXRARG : pos: left 4, [extquanttermlist: (class1)abort:F, discard:T, computed:T]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (class1)]]